CUDA Shared Memory Swizzling

2 comments

• johndough an hour ago

  I was wondering why the author was using braced initialization like

      size_t i{0};
  

  instead of the more common

      size_t i = 0;
  

  Apparently, braced initialization does not allow narrowing conversion, so you'd get a compiler error for e.g. casting double to float

      size_t i{0.0};
  

  and a warning for

      double d = 0.0;
      size_t i{d};
  

  which might silently overflow size_t otherwise, so this is a bit safer.

  In C++, you can get the same effect without the unusual syntax by passing -Wfloat-conversion to gcc/clang, but not sure how to do that with CUDA:

• KeplerBoy 2 hours ago

  Lei Mao's blog is such an amazing resource for GPU performance engineering. I am stunned by the sheer amount of insight he puts out on his blog.